package algorithm.string;

/**
 * 反转字符串
 * <p>
 * 编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。
 * <p>
 * 不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
 * <p>
 * <p>
 * <p>
 */
public class Demo1 {

    /**
     * 示例 1：
     * <p>
     * 输入：s = ["h","e","l","l","o"]
     * 输出：["o","l","l","e","h"]
     * 示例 2：
     * <p>
     * 输入：s = ["H","a","n","n","a","h"]
     * 输出：["h","a","n","n","a","H"]
     * hello
     *
     * @param args
     */
    public static void main(String[] args) {
        char[] chars = new char[]{'h', 'e', 'l', 'l', 'o'};
        reverseString1(chars);
    }

    public static void reverseString(char[] str) {
        int len = str.length;
        for (int i = 0; i < len / 2; i++) {
            char temp = str[i];
            str[i] = str[len - i - 1];
            str[len - i - 1] = temp;
        }
        System.out.println(str);
    }

    public static void reverseString1(char[] str) {
        int len = str.length;
        int i = 0;
        int j = len - 1;
        while (i < j) {
            char c = str[i];
            str[i] = str[j];
            str[j] = c;
            i++;
            j--;
        }
        System.out.println(str);
    }

}
